3x^2+17=130-2x^2

Solution for 3x^2+17=130-2x^2 equation:

3x^2+17=130-2x^2

We move all terms to the left:

3x^2+17-(130-2x^2)=0

We get rid of parentheses

3x^2+2x^2-130+17=0

We add all the numbers together, and all the variables

5x^2-113=0

a = 5; b = 0; c = -113;
Δ = b2-4ac
Δ = 02-4·5·(-113)
Δ = 2260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2260}=\sqrt{4*565}=\sqrt{4}*\sqrt{565}=2\sqrt{565}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{565}}{2*5}=\frac{0-2\sqrt{565}}{10}
=-\frac{2\sqrt{565}}{10}
=-\frac{\sqrt{565}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{565}}{2*5}=\frac{0+2\sqrt{565}}{10}
=\frac{2\sqrt{565}}{10}
=\frac{\sqrt{565}}{5}
$